As Regards to the dragnet Examination question posted here earlier. The solution have been made available with regards to the upcoming Chevron Nigeria Internship test.

As explained before, the chevron internship test will be fully conducted by Dragnet Nigeria therefore, you should be expecting GMAT like question which are really really tough and obviously not time friendly. The solutions for some section in the Dragnet Examination question are given below

**NUMERICAL REASONING SOLUTIONS ****SECTION 2**

- F(2), since company Y spends 12days (5%) of 240 days in conferences, and 1 staff has already spent 10 days, it implies that the remaining staff have just two days to spend in attending conferences before the year runs out.
- A (40days) i.e. 200*70/100 – 200*50/100= 40
- E (22554) i.e. number of staffs that left =90*70/100=63. The detail of each staff will take 358 characters. Therefore for 63 people, 358*63 character worth of space would be left.
- A (8950 characters) i.e. 25 *358 (each staff record requires 358 characters, from question 5)
- B (127) i.e. The First name’s first letter is character 1, and the last letter for home address 4 is character 126. Therefore, the first letter for post code will be character 127.
- A(5.5), if 1 litre of gloss paints 14m
^{2}, 11 by 71.e 77m^{2}will need 77/14 litres of gloss paint. - D(6litres) 1 litre undercoat covers 16m
^{2}, therefore 96m^{2}will require 96/16 litres of undercoat paint. - F (7.5 litres) 1 litres of emulsion covers 12m
^{2}, 90m^{2}(6*15) will need 90/12 - E (10), note, the room is rectangular that means the opposite sides have the same area, therefore (11*3)2+ (9*3)2= 120 which is the total area of the room. Since 1litre of emulsion covers 12m
^{2}, 120m^{2}will need 120/12 litres of emulsion. - A (550), if it trebled to reach 600 in the last year, that means it was 200 b4 the last year, if it quadrupled to reach 200, that means it was 50 b4 then. Since 50 correspond to the 3
^{rd}year, it means that 11 units of the product will cost 11*50 =550 dollars. - B (2,400), price at second year is 100, then price at year three=2*100, price at year 4=4*200 and finally price at year five =800*3=2,400$.
- C (15), price at year 5=720, therefore price at year 4=720/3=240, price in year 3=240/4=60, price at year 2=60/2=30, therefore at year 1=30/2=15.
- F (200), the current price is 600$ and it trebled to get to 600$ therefore the price last year was 200$.
**=**E(305), for year 1 sale after 2nd month= 35,after 4^{th}month= 25, after 6^{th}month=15, after 8^{th}month=15, after 10^{th}month=20, after 12^{th}month=15.

For year 2 sale after 2nd month= 25, after 4^{th}month= 30, after 6^{th}month=25, after 8^{th}month=35, after 10^{th}month=35, after 12^{th}month=30. Therefore total for the two years= the sum of sales for year1 and 2 which is 30.- D(82.5), if sales in year 3 was 50% greater than year 2, it means for every two months in year 3, sales was 50% greater than the corresponding period for year 2, that is, if sales after 4
^{th}month in year 2 is 30, sales after 4^{th}month in year 3= 45(30+ 30*50/100), also if sales after 6^{th}months in year 2= 25, sales after 6^{th}in year 3= 37.5(25+25*50/100). For year, total sales for month 2 and 4=45+37.5=82.5.

(Note that 4^{th}and 6^{th}month corresponds to 2^{nd}and 3^{rd}period on X axis of the graph). - F (4 only), if you subtract sales between corresponding months for year 1 and 2 you’d discover that period 4 records the highest difference in sales.

**Verbal Reasoning Solution Section 3**

**Note the answers are based on what is in the passage, don’t use **

1)C and D 2)B and D 3) A and C 4)C and D 5)A and C 6)C and D 7)A and B 8)A and D 9)A and D 10)B and C 11)A and D 12)A and D 13)A and B 14)A and D 15)C and D 16)B and D 17)C and D 18)A and C 19)B and D 20)B and C

## Abstract Reasoning Solution Section 1

1)D 2)B 3)F 4)D 5)B 6)B 7)C 8)D 9)D 10)D 11)D 12)B 13)C 14)A 15)F 16)D

More solutions will be uploaded with time

## ThankGod

Ok

## ThankGod

The dragnet questions we downloaded is verbal and numerical reasonings so which one is the abstract reasoning? Clarify us on the solutions please…… Thanks

## udo

please guy am finding it difficult to download the dragnet past question please help me out

## Valerian

What’s really the problem. Mr Udo

## Valerian

The abstract reasoning is below the numerical reasoning

## udo

I have downloaded the verbal reasoning but the numerical reasoning keep on reloading the whole page. I will appreciate if it can be send to my email: ukonuokorie0 @gmail.com, thanks

## ThankGod

The verbal reasoning answers are not corresponding aspirants pls check it well

## Andy

Good day, Please i’m finding it difficult downloading the numerical reasoning aptitude test. Keeps referring me to another page. will appreciate it if it can be sent to mail. andiokwere@gmail.com. Thanks for your continuous assistance.

## Valerian

Good day all, there is no need for this solution as the concise dragnet past questions together with the answers has been updated. You can download it using the link below

https://scholarification.com/download-compilation-of-dragnet-examination-past-questions-for-agip-shell-mobil-chevron-scholarships-and-internships-exams/