As Regards to the dragnet Examination question posted here earlier. The solution have been made available with regards to the upcoming Chevron Nigeria Internship test.
As explained before, the chevron internship test will be fully conducted by Dragnet Nigeria therefore, you should be expecting GMAT like question which are really really tough and obviously not time friendly. The solutions for some section in the Dragnet Examination question are given below
NUMERICAL REASONING SOLUTIONS SECTION 2
- C (can’t tell from data)
- D (96), since 40% of working days out of 240 days is spent meeting clients in company X. 40% of 240= 96.
- F(2), since company Y spends 12days (5%) of 240 days in conferences, and 1 staff has already spent 10 days, it implies that the remaining staff have just two days to spend in attending conferences before the year runs out.
- A (40days) i.e. 200*70/100 – 200*50/100= 40
- E (22554) i.e. number of staffs that left =90*70/100=63. The detail of each staff will take 358 characters. Therefore for 63 people, 358*63 character worth of space would be left.
- A (8950 characters) i.e. 25 *358 (each staff record requires 358 characters, from question 5)
- B (127) i.e. The First name’s first letter is character 1, and the last letter for home address 4 is character 126. Therefore, the first letter for post code will be character 127.
- C (99), each employee record need 358, therefore 35,700 will be for 35700/358 number of employee.
- A(5.5), if 1 litre of gloss paints 14m2, 11 by 71.e 77m2 will need 77/14 litres of gloss paint.
- D(6litres) 1 litre undercoat covers 16m2, therefore 96m2 will require 96/16 litres of undercoat paint.
- F (7.5 litres) 1 litres of emulsion covers 12m2, 90m2(6*15) will need 90/12
- E (10), note, the room is rectangular that means the opposite sides have the same area, therefore (11*3)2+ (9*3)2= 120 which is the total area of the room. Since 1litre of emulsion covers 12m2, 120m2 will need 120/12 litres of emulsion.
- A (550), if it trebled to reach 600 in the last year, that means it was 200 b4 the last year, if it quadrupled to reach 200, that means it was 50 b4 then. Since 50 correspond to the 3rd year, it means that 11 units of the product will cost 11*50 =550 dollars.
- B (2,400), price at second year is 100, then price at year three=2*100, price at year 4=4*200 and finally price at year five =800*3=2,400$.
- C (15), price at year 5=720, therefore price at year 4=720/3=240, price in year 3=240/4=60, price at year 2=60/2=30, therefore at year 1=30/2=15.
- F (200), the current price is 600$ and it trebled to get to 600$ therefore the price last year was 200$.
- =E(305), for year 1 sale after 2nd month= 35,after 4th month= 25, after 6th month=15, after 8th month=15, after 10th month=20, after 12th month=15.
For year 2 sale after 2nd month= 25, after 4th month= 30, after 6th month=25, after 8th month=35, after 10th month=35, after 12th month=30. Therefore total for the two years= the sum of sales for year1 and 2 which is 30.
- D(82.5), if sales in year 3 was 50% greater than year 2, it means for every two months in year 3, sales was 50% greater than the corresponding period for year 2, that is, if sales after 4th month in year 2 is 30, sales after 4th month in year 3= 45(30+ 30*50/100), also if sales after 6th months in year 2= 25, sales after 6th in year 3= 37.5(25+25*50/100). For year, total sales for month 2 and 4=45+37.5=82.5.
(Note that 4th and 6th month corresponds to 2nd and 3rd period on X axis of the graph).
- A(12.5), subtract the sales for each corresponding month in between year 1 and 2 then sum them and divide by 6.i.e 35-25+30-25+25-15+35-15+35-20+30-15=75, then 75/6=12.5
- F (4 only), if you subtract sales between corresponding months for year 1 and 2 you’d discover that period 4 records the highest difference in sales.
Verbal Reasoning Solution Section 3
Note the answers are based on what is in the passage, don’t use
1)C and D 2)B and D 3) A and C 4)C and D 5)A and C 6)C and D 7)A and B 8)A and D 9)A and D 10)B and C 11)A and D 12)A and D 13)A and B 14)A and D 15)C and D 16)B and D 17)C and D 18)A and C 19)B and D 20)B and C
Abstract Reasoning Solution Section 1
1)D 2)B 3)F 4)D 5)B 6)B 7)C 8)D 9)D 10)D 11)D 12)B 13)C 14)A 15)F 16)D
More solutions will be uploaded with time